Learning objectives
Section Key Terms
| blackbody | quantized | quantum | ultraviolet catastrophe |
Blackbodies
Our first story of curious significance begins with a T-shirt. You are likely aware that wearing a tight black T-shirt outside on a hot day provides a significantly less comfortable experience than wearing a white shirt. Black shirts, as well as all other black objects, will absorb and re-emit a significantly greater amount of radiation from the sun. This shirt is a good approximation of what is called a blackbody.
A perfect blackbody is one that absorbs and re-emits all radiated energy that is incident upon it. Imagine wearing a tight shirt that did this! This phenomenon is often modeled with quite a different scenario. Imagine carving a small hole in an oven that can be heated to very high temperatures. As the temperature of this container gets hotter and hotter, the radiation out of this dark hole would increase as well, re-emitting all energy provided it by the increased temperature. The hole may even begin to glow in different colors as the temperature is increased. Like a burner on your stove, the hole would glow red, then orange, then blue, as the temperature is increased. In time, the hole would continue to glow but the light would be invisible to our eyes. This container is a good model of a perfect blackbody.
It is the analysis of blackbodies that led to one of the most consequential discoveries of the twentieth century. Take a moment to carefully examine Figure_21_01_Blackbody. What relationships exist? What trends can you see? The more time you spend interpreting this figure, the closer you will be to understanding quantum physics!
View original figure (external; image not reproduced in this text edition)
Original figure description: A graph plotting radiation intensity against wavelength is shown. On the graph, there are three lines, each one corresponding to the temperature of a different radiator. Each of the three lines curves sharply upward and then gradually back downward. This shows two things: First, for each temperature, there is energy emitted across the electromagnetic section. Second, there is a peak wavelength, where the radiation intensity is greatest. On the graph it can be seen that as temperatures get hotter, the peak wavelength shifts to the left of the visible spectrum.
Understanding Blackbody Graphs
Figure_21_01_Blackbody is a plot of radiation intensity against radiated wavelength. In other words, it shows how the intensity of radiated light changes when a blackbody is heated to a particular temperature.
It may help to just follow the bottom-most red line labeled 3,000 K, red hot. The graph shows that when a blackbody acquires a temperature of 3,000 K, it radiates energy across the electromagnetic spectrum. However, the energy is most intensely emitted at a wavelength of approximately 1000 nm. This is in the infrared portion of the electromagnetic spectrum. While a body at this temperature would appear red-hot to our eyes, it would truly appear ‘infrared-hot’ if we were able to see the entire spectrum.
A few other important notes regarding Figure_21_01_Blackbody:
- As temperature increases, the total amount of energy radiated increases. This is shown by examining the area underneath each line.
- Regardless of temperature, all red lines on the graph undergo a consistent pattern. While electromagnetic radiation is emitted throughout the spectrum, the intensity of this radiation peaks at one particular wavelength.
- As the temperature changes, the wavelength of greatest radiation intensity changes. At 4,000 K, the radiation is most intense in the yellow-green portion of the spectrum. At 6,000 K, the blackbody would radiate white hot, due to intense radiation throughout the visible portion of the electromagnetic spectrum. Remember that white light is the emission of all visible colors simultaneously.
- As the temperature increases, the frequency of light providing the greatest intensity increases as well. Recall the equation Because the speed of light is constant, frequency and wavelength are inversely related. This is verified by the leftward movement of the three red lines as temperature is increased.
While in science it is important to categorize observations, theorizing as to why the observations exist is crucial to scientific advancement. Why doesn’t a blackbody emit radiation evenly across all wavelengths? Why does the temperature of the body change the peak wavelength that is radiated? Why does an increase in temperature cause the peak wavelength emitted to decrease? It is questions like these that drove significant research at the turn of the twentieth century. And within the context of these questions, Max Planck discovered something of tremendous importance.
Planck’s Revolution
The prevailing theory at the time of Max Planck’s discovery was that intensity and frequency were related by the equation This equation, derived from classical physics and using wave phenomena, infers that as wavelength increases, the intensity of energy provided will decrease with an inverse-squared relationship. This relationship is graphed in Figure_21_01_Comparison and shows a troubling trend. For starters, it should be apparent that the graph from this equation does not match the blackbody graphs found experimentally. Additionally, it shows that for an object of any temperature, there should be an infinite amount of energy quickly emitted in the shortest wavelengths. When theory and experimental results clash, it is important to re-evaluate both models. The disconnect between theory and reality was termed the ultraviolet catastrophe.
View original figure (external; image not reproduced in this text edition)
Original figure description: A graph plotting intensity of spectral radiation (or, loosely speaking, brightness) vs wavelength is shown. There is another line shown, called ‘Classical Theory.’ This line starts at the right of the graph and curves sharply upward and to the left. It appears to reach an infinite value around 1.2 micrometers.
Due to concerns over the ultraviolet catastrophe, Max Planck began to question whether another factor impacted the relationship between intensity and wavelength. This factor, he posited, should affect the probability that short wavelength light would be emitted. Should this factor reduce the probability of short wavelength light, it would cause the radiance curve to not progress infinitely as in the classical theory, but would instead cause the curve to precipitate back downward as is shown in the 5,000 K, 4,000 K, and 3,000 K temperature lines of the graph in Figure_21_01_Comparison. Planck noted that this factor, whatever it may be, must also be dependent on temperature, as the intensity decreases at lower and lower wavelengths as the temperature increases.
The determination of this probability factor was a groundbreaking discovery in physics, yielding insight not just into light but also into energy and matter itself. It would be the basis for Planck’s 1918 Nobel Prize in Physics and would result in the transition of physics from classical to modern understanding. In an attempt to determine the cause of the probability factor, Max Planck constructed a new theory. This theory, which created the branch of physics called quantum mechanics, speculated that the energy radiated by the blackbody could exist only in specific numerical, or quantum, states. This theory is described by the equation where n is any nonnegative integer (0, 1, 2, 3, …) and h is Planck’s constant, given by and f is frequency.
Through this equation, Planck’s probability factor can be more clearly understood. Each frequency of light provides a specific quantized amount of energy. Low frequency light, associated with longer wavelengths would provide a smaller amount of energy, while high frequency light, associated with shorter wavelengths, would provide a larger amount of energy. For specified temperatures with specific total energies, it makes sense that more low frequency light would be radiated than high frequency light. To a degree, the relationship is like pouring coins through a funnel. More of the smaller pennies would be able to pass through the funnel than the larger quarters. In other words, because the value of the coin is somewhat related to the size of the coin, the probability of a quarter passing through the funnel is reduced!
Furthermore, an increase in temperature would signify the presence of higher energy. As a result, the greater amount of total blackbody energy would allow for more of the high frequency, short wavelength, energies to be radiated. This permits the peak of the blackbody curve to drift leftward as the temperature increases, as it does from the 3,000 K to 4,000 K to 5,000 K values. Furthering our coin analogy, consider a wider funnel. This funnel would permit more quarters to pass through and allow for a reduction in concern about the probability factor.
In summary, it is the interplay between the predicted classical model and the quantum probability that creates the curve depicted in Figure_21_01_Comparison. Just as quarters have a higher currency denomination than pennies, higher frequencies come with larger amounts of energy. However, just as the probability of a quarter passing through a fixed diameter funnel is reduced, so is the probability of a high frequency light existing in a fixed temperature object. As is often the case in physics, it is the balancing of multiple incredible ideas that finally allows for better understanding.
Quantization
It may be helpful at this point to further consider the idea of quantum states. Atoms, molecules, and fundamental electron and proton charges are all examples of physical entities that are quantized—that is, they appear only in certain discrete values and do not have every conceivable value. On the macroscopic scale, this is not a revolutionary concept. A standing wave on a string allows only particular harmonics described by integers. Going up and down a hill using discrete stair steps causes your potential energy to take on discrete values as you move from step to step. Furthermore, we cannot have a fraction of an atom, or part of an electron’s charge, or 14.33 cents. Rather, everything is built of integral multiples of these substructures.
That said, to discover quantum states within a phenomenon that science had always considered continuous would certainly be surprising. When Max Planck was able to use quantization to correctly describe the experimentally known shape of the blackbody spectrum, it was the first indication that energy was quantized on a small scale as well. This discovery earned Planck the Nobel Prize in Physics in 1918 and was such a revolutionary departure from classical physics that Planck himself was reluctant to accept his own idea. The general acceptance of Planck’s energy quantization was greatly enhanced by Einstein’s explanation of the photoelectric effect (discussed in the next section), which took energy quantization a step further.
View original figure (external; image not reproduced in this text edition)
Original figure description: A photo of Max Planck sitting at a desk is shown. The photo is taken from his side and he appears to be reading a document.
How does Photon Energy Change with Various Portions of the EM Spectrum?
Refer to the Graphs of Blackbody Radiation shown in the first figure in this section. Compare the energy necessary to radiate one photon of infrared light and one photon of visible light.
Strategy
To determine the energy radiated, it is necessary to use the equation It is also necessary to find a representative frequency for infrared light and visible light.
Solution
According to the first figure in this section, one representative wavelength for infrared light is 2000 nm (2.000 × 10-6 m). The associated frequency of an infrared light is
Using the equation , the energy associated with one photon of representative infrared light is
The same process above can be used to determine the energy associated with one photon of representative visible light. According to the first figure in this section, one representative wavelength for visible light is 500 nm.
Discussion
This example verifies that as the wavelength of light decreases, the quantum energy increases. This explains why a fire burning with a blue flame is considered more dangerous than a fire with a red flame. Each photon of short-wavelength blue light emitted carries a greater amount of energy than a long-wavelength red light. This example also helps explain the differences in the 3,000 K, 4,000 K, and 6,000 K lines shown in the first figure in this section. As the temperature is increased, more energy is available for a greater number of short-wavelength photons to be emitted.
Practice Problems
An AM radio station broadcasts at a frequency of 1,530 kHz . What is the energy in Joules of a photon emitted from this station?
- 10.1 × 10-26 J
- 1.01 × 10-28 J
- 1.01 × 10-29 J
- 1.01 × 10-27 J
A photon travels with energy of 1.0 eV. What type of EM radiation is this photon?
- visible radiation
- microwave radiation
- infrared radiation
- ultraviolet radiation
Check Your Understanding
Do reflective or absorptive surfaces more closely model a perfect blackbody?
- reflective surfaces
- absorptive surfaces
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Why do we not notice quantization of photons in everyday experience?
- because the size of each photon is very large
- because the mass of each photon is so small
- because the energy provided by photons is very large
- because the energy provided by photons is very small
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Section Summary
- A blackbody will radiate energy across all wavelengths of the electromagnetic spectrum.
- Radiation of a blackbody will peak at a particular wavelength, dependent on the temperature of the blackbody.
- Analysis of blackbody radiation led to the field of quantum mechanics, which states that radiated energy can only exist in discrete quantum states.
Key Equations
| quantum energy |
Concept Items
What aspect of the blackbody spectrum forced Planck to propose quantization of energy levels in atoms and molecules?
- Radiation occurs at a particular frequency that does not change with the energy supplied.
- Certain radiation occurs at a particular frequency that changes with the energy supplied.
- Maximum radiation would occur at a particular frequency that does not change with the energy supplied.
- Maximum radiation would occur at a particular frequency that changes with the energy supplied.
Two lasers shine red light at 650 nm. One laser is twice as bright as the other. Explain this difference using photons and photon energy.
- The brighter laser emits twice the number of photons and more energy per photon.
- The brighter laser emits twice the number of photons and less energy per photon.
- Both lasers emit equal numbers of photons and equivalent amounts of energy per photon.
- The brighter laser emits twice the number of photons but both lasers emit equivalent amounts of energy per photon.
Consider four stars in the night sky: red, yellow, orange, and blue. The photons of which star will carry the greatest amount of energy?
- blue
- orange
- red
- yellow
A lightbulb is wired to a variable resistor. What will happen to the color spectrum emitted by the bulb as the resistance of the circuit is increased?
- The bulb will emit greener light.
- The bulb will emit bluer light.
- The bulb will emit more ultraviolet light.
- The bulb will emit redder light.
Critical Thinking
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Why does the intensity shown in the blackbody radiation graph decrease after its peak frequency is achieved?
View original figure (external; image not reproduced in this text edition)
Original figure description: A graph of blackbody radiation that shows curves of the intensity of E M radiation versus wavelength in nanometers.
- Because after reaching the peak frequency, the photons created at a particular frequency are too many for energy intensity to continue to decrease.
- Because after reaching the peak frequency, the photons created at a particular frequency are too few for energy intensity to continue to decrease.
- Because after reaching the peak frequency, the photons created at a particular frequency are too many for energy intensity to continue to increase.
- Because after reaching the peak frequency, the photons created at a particular frequency are too few for energy intensity to continue to increase.
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Why is it assumed that a perfect absorber of light (like a blackbody) must also be a perfect emitter of light?
- To achieve electrostatic equilibrium with its surroundings
- To achieve thermal equilibrium with its surroundings
- To achieve mechanical equilibrium with its surroundings
- To achieve chemical equilibrium with its surroundings
Problems
How many X-ray photons per second are created by an X-ray tube that produces a flux of X-rays having a power of 1.00 W? Assume the average energy per photon is 75.0 keV.
- 8.33 × 1015 photons
- 9.1 × 107 photons
- 9.1 × 108 photons
- 8.33 × 1013 photons
What is the frequency of a photon produced in a CRT using a 25.0-kV accelerating potential? This is similar to the layout as in older color television sets.
- 6.04 × 10−48 Hz
- 2.77 × 10−48 Hz
- 3.02 × 1018 Hz
- 6.04 × 1018 Hz
Test Prep Multiple Choice
A perfect blackbody is a perfect absorber of energy transferred by what method?
- conduction
- convection
- induction
- radiation
Which of the following is a physical entity that is quantized?
- electric charge of an ion
- frequency of a sound
- speed of a car
Find the energy in joules of photons of radio waves that leave an FM station that has a 90.0-MHz broadcast frequency.
- 1.8 × 10−25 J
- 1.11 × 10−25 J
- 7.1 × 10−43 J
- 5.96 × 10-26 J
Which region of the electromagnetic spectrum will provide photons of the least energy?
- infrared light
- radio waves
- ultraviolet light
- X-rays
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Given two stars of equivalent size, which will have a greater temperature: a red dwarf or a yellow dwarf? Explain. Note—Our sun is considered a yellow dwarf.
- a yellow dwarf, because yellow light has lower frequency
- a red dwarf, because red light has lower frequency
- a red dwarf, because red light has higher frequency
- a yellow dwarf, because yellow light has higher frequency
Test Prep Short Answer
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Because there are more gradations to high frequency radiation than low frequency radiation, scientists also thought it possible that a curve titled the ultraviolet catastrophe would occur. Explain what the blackbody radiation curve would look like if this were the case.
- The curve would steadily increase in intensity with increasing frequency.
- The curve would steadily decrease in intensity with increasing frequency.
- The curve would be much steeper than in the blackbody radiation graph.
- The curve would be much flatter than in the blackbody radiation graph.
Energy provided by a light exists in the following quantities: 150 J, 225 J, 300 J. Define one possible quantum of energy and provide an energy state that cannot exist with this quantum.
- 65 J; 450 J cannot exist
- 70 J; 450 J cannot exist
- 75 J; 375 J cannot exist
- 75 J; 100 J cannot exist
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How many 500-mm microwave photons are needed to supply the 8 kJ of energy necessary to heat a cup of water by 10 degrees Celsius?
- 8.05 × 1028 photons
- 8.05 × 1026 photons
- 2.01 × 1026 photons
- 2.01 × 1028 photons
What is the efficiency of a 100-W, 550-nm lightbulb if a photometer finds that 1 × 1020 photons are emitted each second?
- 101 percent
- 72 percent
- 18 percent
- 36 percent
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Test Prep Extended Response
Some television tubes are CRTs. They use an approximately 30-kV accelerating potential to send electrons to the screen, where the electrons stimulate phosphors to emit the light that forms the pictures we watch. Would you expect X-rays also to be created? Explain.
- No, because the full spectrum of EM radiation is not emitted at any temperature.
- No, because the full spectrum of EM radiation is not emitted at certain temperatures.
- Yes, because the full spectrum of EM radiation is emitted at any temperature.
- Yes, because the full spectrum of EM radiation is emitted at certain temperatures.
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What is the accelerating voltage of an X-ray tube that produces X-rays with the shortest wavelength of 0.0103 nm?
- 1.21 × 1010 V
- 2.4 × 105 V
- 3.0 × 10−33 V
- 1.21 × 105 V
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Glossary
- blackbody
- object that absorbs all radiated energy that strikes it and also emits energy across all wavelengths of the electromagnetic spectrum
- quantized
- the fact that certain physical entities exist only with particular discrete values and not every conceivable value
- quantum
- discrete packet or bundle of a physical entity such as energy
- ultraviolet catastrophe
- misconception that blackbodies would radiate high frequency energy at a much higher rate than energy radiated at lower frequencies